Question 4 the day : June 10, 2003

The question for the day is from the topic of Number Systems.

Question
How many different factors are there for the number 48, excluding 1 and 48?

(1) 12
(2) 4
(3) 8
(4) None of these

Correct Choice is (3) and the correct answer is 8

Explanatory Answers

To find the number of factors of a given number, express the number as a product of powers of prime numbers.

In this case, 48 can be written as 16 * 3 = (2⁴ * 3)

Now, increment the power of each of the prime numbers by 1 and multiply the result.

In this case it will be (4 + 1)*(1 + 1) = 5 * 2 = 10 (the power of 2 is 4 and the power of 3 is 1)

Therefore, there will 10 factors including 1 and 48. Excluding, these two numbers, you will have 10 - 2 = 8 factors.

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