Factors/divisors - Quant/Math - CAT 2007
Question 4 the day : June 22, 2005
The question for the day is a question on factors/divisors of a number in the topic number theory.
Question
If both 11 2 and 3 3 are factors of the number a * 4 3 * 6 2 * 13 11, then what is the smallest possible value of a?
- 121
- 3267
- 363
- 33
Correct choice (3). Correct Answer - (363)
Explanatory Answers
112 is a factor of the given number. The number does not have a power or multiple of 11 as its factor. Hence, "a" should include 112
33 is a factor of the given number. 62 is a part of the number. 62 has 32 in it. Therefore, if 33 has to be a factor of the given number a * 43 * 62 * 1311, then we will need at least another 3.
Therefore, if "a" should be at least 112 * 3 = 363 if the given number has to have 112 and 33 as its factors.
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