Question 4 the day : August 07, 2003

The question for the day is from the topic of Number Systems. It is a question on odd and even numbers and operations on these numbers.

Question
Let x, y and z be distinct integers. x and y are odd and positive, and z is even and positive. Which one of the following statements cannot be true?

(1) (x-z)² y is even
(2) (x-z)y² is odd
(3) (x-z)y is odd
(4) (x-y)²z is even

Correct Choice is (1) and Correct Answer is (x-z)² y is even

Explanatory Answer

x and y are odd and positive and z is even and positive

(x - z)² y is even cannot true

x - z is odd and y is odd
Therefore, (x - z)² will be odd and (x - z)² y will be odd

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