Percentages : XAT 2016 / XAT 2016 Math Practice Question
This question is an arithmetic question from the topic Percentages.
Peter got 30% of the maximum marks in an examination and failed by 10 marks. However, Paul who took the same examination got 40% of the total marks and got 15 marks more than the passing marks. What was the passing marks in the examination?
. Choice (4)
Let 'x' be the maximum marks in the examination.
Therefore, Peter got 30% of x =
And Paul got 40% of x =
In terms of the maximum marks Paul got 0.4x - 0.3x = 0.1x more than Peter. -- (1)
The problem however, states that Paul got 15 marks more than the passing mark and Peter got 10 marks less than the passing mark.
Therefore, Paul has got 15 + 10 = 25 marks more than Peter. -- (2)
Equating (1) and (2), we get
0.1x = 25 => x =
'x' is the maximum mark and is equal to 250 marks.
We know that Peter got 30% of the maximum marks.
Therefore, Peter got
= 75 marks.
We also know that Peter got 10 marks less than the passing mark.
Therefore, the passing mark will be 10 marks more than what Peter got = 75 + 10 = 85.
Correct Answer (4)
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