Permutation and Combination - Quant/Math - CAT 2016
Question 4 the day:
October 08, 2003
The question for the day is from the topic Permutation and Combination.
Question:
- How many words of 4 consonants and 3 vowels can be made from 12 consonants and 4 vowels, if all the letters are different?
(1) 16C7 * 7!
(2) 12C4 * 4C3 * 7!
(3) 12C3 * 4C4
(4) 12C4 * 4C3
Correct Answer - (2)
Solution:
4 consonants out of 12 can be selected in 12C4 ways.
3 vowels can be selected in 4C3 ways.
Therefore, total number of groups each containing 4 consonants and 3 vowels = 12C4 * 4C3
Each group contains 7 letters, which can be arranging in 7! ways.
Therefore required number of words = 124 * 4C3 * 7!
XLRI XAT TANCET Practice Question Samples
Sorted by Subject
Algebra,
Arithmetic & Geometric Progressions,
Averages and Mean,
Clocks and Calendars,
Data Sufficiency,
English Grammar,
Function,
Geometry,
Coordinate Geometry,
Mensuration,
Trigonometry,
Interest,
Inequality,
Mixtures & Alligations,
Number System and Theory,
Percentages,
Profit & Loss,
Permutation & Combination,
Probability,
Ratio, Proportion,
Set Language and Theory,
Speed, Time & Distance,
Races,
Pipes & Cisterns And Work & Time,
Miscellaneous,
General Knowledge.
|
|
Quick Links
GMAT Math eBook Series |
|
GMAT Math eBooks series on high scoring topics such as permutation combination, number theory, geometry. US$ 6.99.
|
|
|