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Interest - Quant/Math - TANCET 2020 / TANCET 2020 Practice Question

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This question is from the topic of compound interest and is about compounded rates of growth.

The population of a town was 3600 three years back. It is 4800 right now. What will be the population three years down the line, if the rate of growth of population has been constant over the years and has been compounding annually?
(1) 6000   (2) 6400   (3) 7200   (4) 9600
Correct Answer - (2)


Solution:

The population grew from 3600 to 4800 in 3 years. That is a growth of 1200 on 3600 during three year span.

Therefore, the rate of growth for three years has been 1200/3600 = 1/3
The rate of growth during the next three years will also be the same.
Therefore, the population will grow from 4800 by 1/3 * 4800 = 1600
Hence, the population three years from now will be 4800 + 1600 = 6400.

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